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Research Article

Fibonacci Ideal Convergence on Intuitionistic Fuzzy Normed Linear Spaces

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Pages 255-268 | Received 10 Jul 2019, Accepted 11 Dec 2022, Published online: 29 Dec 2022

Abstract

The main goal of this article is to present the notion of Fibonacci I-convergence of sequences on intuitionistic fuzzy normed linear space. To accomplish this goal, we mainly investigate some fundamental properties of the newly introduced notion. Then, we examine the Fibonacci I-Cauchy sequences and Fibonacci I completeness in the construction of an intuitionistic fuzzy normed linear space. Some intuitionistic fuzzy Fibonacci ideal convergent spaces have been established. Further, we prove on some algebraic and topological features of these convergent sequence spaces.

1991 Mathematics subject classifications:

1. Introduction and Background

The initial work on the statistical convergence of sequences was carried out by Fast [Citation1]. Schoenberg [Citation2] validated a number of elementary properties of statistical convergence and represented this notion as a method of summability.

The notion of I-convergence initially originated in the study of Kostyrko et al. [Citation3]. Kostyrko et al. [Citation4] proposed and proved some new properties of I-convergence and introduced extremal I-limit points. Further, the study was extended by S˘alát et al. [Citation5], Tripathy and Hazarika [Citation6] and many others.

Fibonacci sequences were published by Fibonacci in the book ‘Liber Abaci’. The Fibonacci sequences were earlier stated as Virahanka numbers by Indian mathematics [Citation7]. The sequence (1,1,2,3,5,8,13,21,34,55,89,144,) is known as the Fibonacci sequence [Citation8]. The Fibonacci numbers may be given by the following relation: fn=fn+1fn2 for some integers n2.

Some properties of Fibonacci numbers are given by limnfn+1fn=1+52=α,(Goldenratio)k=0nfk=fn+21(nN),k1fkconverges,fn1fn+1fn2=(1)n+1,n1.(Cassiniformula) The first application of Fibonacci sequence in the sequence spaces was given by Kara and Başarır [Citation9]. Then, Kara [Citation10] obtained the Fibonacci difference matrix F^ via Fibonacci sequence (fn) for n{1,2,3,}, and studied some new sequence spaces in this connection. The definition of statistical convergence using the Fibonacci sequence was introduced in [Citation11]. Some works on spaces connected Fibonacci sequence can be found in [Citation12–15].

Kara [Citation10] defined the infinite matrix F^=(f^kn) by f^kn={fk+1fk,n=k1fkfk+1,n=k0,0n<k1orn>k, where fk is the kth Fibonacci number for every kN.

The Fibonacci sequence of numbers and the associated ‘Golden Ratio’ are observed in nature. We examine that various natural things follow the Fibonacci sequence. It appears in biological settings such as branching in trees, the flowering of an artichoke and the arrangement of a pine cone's bracts etc. Nowadays Fibonacci numbers play a very significant role in coding theory. Fibonacci numbers in different forms are extensively applied in constructing security coding. The Fibonacci Numbers are also applied in Pascal's Triangle. Amazing applications can be examined in [Citation16].

After the advent of fuzzy set theory by Zadeh [Citation17], fuzzy logic has found its applications in some subbranches of mathematics like topological spaces [Citation18–20], theory of functions [Citation21,Citation22] and approximation theory [Citation23].

Fuzzy set theory has found large-scale applications in many fields of science and engineering, such as computer programming [Citation24], non-linear operators [Citation25], population changes [Citation26], control of chaos [Citation27], and quantum physics [Citation28].

The intuitionistic fuzzy sets were focused on by Atanassov [Citation29], and it has been utilized in decision-making problems [Citation30], E-infinity theory of high-energy physics [Citation31]. In intuitionistic fuzzy sets (IFSs) the ‘degree of non-belongingness’ is not independent but it is dependent on the ‘degree of belongingness’. Fuzzy sets (FSs) can be thought as a remarkable case of an IFS where the ‘degree of non-belongingness’ of an element is absolutely equal to ‘1-degree of belongingness’. Uncertainty is based on the belongingness degree in IFSs. An intuitionistic fuzzy metric space was considered by Park [Citation32]. Saadati and Park [Citation33] obtained an intuitionistic fuzzy normed linear space (IFNLS for short). Karakuş et al. [Citation34] studied statistical convergence in IFNLS and Mursaleen et al. [Citation35] studied the statistical convergence of double sequences in IFNLS. Some works related to the convergence of sequences in a few IFNLS can be found in [Citation36–44].

Recently, Kirişci [Citation45] studied the Fibonacci statistical convergence on IFNLS. He defined the Fibonacci statistically Cauchy sequences in an IFNLS and investigated the Fibonacci statistical completeness of the space.

Firstly, some basic definitions of this paper can be seen in [Citation3,Citation33,Citation41,Citation45].

2. Main Results

In this section, we give the Fibonacci I-convergence in an IFNLS.

Definition 2.1

Let (X,ϕ,ψ,,) be an IFNLS and IP(N) be a nontrivial ideal. A sequence x=(xk) in X is said to be Fibonacci I-convergence with regards to the intuitionistic fuzzy norm (IFN) (ϕ,ψ) (briefly, FIC-IFN), if there is a number ξX such that for every p>0 and ε(0,1), the set Kε(F^):={kN:ϕ(F^xkξ,p)1εorψ(F^xkξ,p)ε}I. We write IFI(ϕ,ψ)limxk=ξ. The set of FIC-IFN will be demonstrated by I(F^)IFN.

Example 2.1

Taking I={AN:δ(A)=0}, I is an admissible ideal in N and so Fibonacci I-convergence coincides with Fibonacci statistical convergence in an IFNLS.

Example 2.2

Let (X,.) be a normed space and kl=kl and kl=min{k+l,1}, k,l[0,1]. Any xX and p>0, consider ϕ(x,p):=pp+x,ψ(x,p):=xp+x. Then, (X,ϕ,ψ,,) be an IFNLS. Define the F^xk=(fk+12)=(1,22,32,52,). Since fk+12 as k and F^x=(1,0,0,), then F^xI(F^)IFN. Consider Ak(ε,p):={kN:ϕ(F^xk,p)1εorψ(F^xk,p)ε} for ε(0,1) and for all p>0. When k becomes sufficiently large, the quantity ϕ(F^xkξ,p) becomes less than 1ε and similarly the quantity ψ(F^xkξ,p) becomes greater than ε. So, for ε>0 and p>0, Aε(F^)I.

Now, we investigate the sequence spaces in IFNLS as the sets of sequences whose F^-transforms are in the spaces c0I(ϕ,ψ), cI(ϕ,ψ) and lI(ϕ,ψ). In addition, we put forward some inclusion theorems and obtain various topological and algebraic features from these results. Assume that a sequence x=(xk)ω and I is an admissible ideal of a subset of N. We identify c0(ϕ,ψ)I(F^)={x=(xk)ω:{kN:ϕ(F^xk,p)1εorψ(F^xk,p)ε}I},c(ϕ,ψ)I(F^)={x=(xk)ω:{kN:ϕ(F^xkξ,p)1εorψ(F^xkξ,p)εforsomeξR}I},l(ϕ,ψ)I(F^)={x=(xk)ω:M>0sothat{kN:ϕ(F^xk,p)1Morψ(F^xk,p)M}I}.

Theorem 2.1

Let (X,ϕ,ψ,,) be an IFNLS. The inclusion relation c0(ϕ,ψ)I(F^)c(ϕ,ψ)I(F^)l(ϕ,ψ)I(F^) supplies.

Proof.

It can be observed that c0(ϕ,ψ)I(F^)c(ϕ,ψ)I(F^). We only denote that c(ϕ,ψ)I(F^)l(ϕ,ψ)I(F^). Take x=(xk)c(ϕ,ψ)I(F^). Then, there is ξX so that IFI(ϕ,ψ)limxk=ξ. So, for all p>0 and ε(0,1), the set K={kN:ϕ(F^xkξ,p2)>1εandψ(F^xkξ,p2)<ε}F(I). ϕ(ξ,p2)=s and ψ(ξ,p2)=t for all p>0. As s,t(0,1) and ε(0,1), there exist u1,u2(0,1) such that (1ε)s>1u1 and εt<u2. As a result, for p>0 and ε(0,1), we obtain ϕ(F^xk,p)=ϕ(F^xk+ξξ,p)ϕ(F^xkξ,p2)ϕ(ξ,p2)>(1ε)s>1u1 and ψ(F^xk,p)=ψ(F^xk+ξξ,p)ψ(F^xkξ,p2)ψ(ξ,p2)<εt<u2. Taking u=max{u1,u2}, we get the set {x=(xk)ω:u>0sothat{kN:ϕ(F^xk,p)>1uandψ(F^xk,p)<u}F(I).} Hence, x=(xk)l(ϕ,ψ)I(F^) implies c(ϕ,ψ)I(F^)l(ϕ,ψ)I(F^).

The converse of the inclusion relation does not supply. We establish the following example to prove our claim.

Example 2.3

Assume (X=R,.) be a normed space such that x=supk|xk|. Suppose kl=min{k,l} and kl=max{k,l} for each k,l[0,1]. Identify the norm (ϕ,ψ) on X2×(0,) as follows ϕ(x,p):=pp+x,ψ(x,p):=xp+x. Then, (X,ϕ,ψ,,) is an IFNS. Define the sequence F^x=(1,0,0,), it can be easily observed that (xk)c(ϕ,ψ)I(F^) and IFI(ϕ,ψ)limxk=1, but (xk)c0(ϕ,ψ)I(F^).

Example 2.4

Suppose (X=R,.) be a normed space and (ϕ,ψ) be the IFN as determined in the above example. Examine the sequence (xk)=(1)k. Then (xk)l(ϕ,ψ)I(F^), but (xk)c(ϕ,ψ)I(F^).

Lemma 2.1

Let (X,ϕ,ψ,,) be an IFNLS. For all ε>0 and p>0, the following statements are equivalent:

(a)

IFI(ϕ,ψ)limxk=ξ;

(b)

{kN:ϕ(F^xkξ,p)1ε}I and {kN:ψ(F^xkξ,p)ε}I;

(c)

{kN:ϕ(F^xkξ,p)>1εandψ(F^xkξ,p)<ε}F(I),

(d)

{kN:ϕ(F^xkξ,p)>1ε}F(I)and{kN:ψ(F^xkξ,p)<ε}F(I) and

(e)

IFI(ϕ,ψ)limϕ(F^xkξ,p)=1 and IFI(ϕ,ψ)limω(F^xkξ,p)=0.

Proof.

It is easy to demonstrate the equivalence of (a)–(d). Here, we just prove the equivalence of (b) and (e). Let (b) holds. For every ε>0 and p>0, we get {kN:|ϕ(F^xkξ,p)1|ε}={kN:ϕ(F^xkξ,p)1+ε}{kN:ϕ(F^xkξ,p)1ε} and for every ε>0 the set {kN:ϕ(F^xkξ,p)1+ε}=I, it follows together with (b) that {kN:|ϕ(F^xkξ,p)1|ε}I. Hence, we have IFI(μ,v)limϕ(F^xkξ,p)=1. In a similar way, for all ε>0 and p>0, {kN:|ψ(F^xkξ,p)0|ε}={kN:ψ(F^xkξ,p)ε}{kN:ψ(F^xkξ,p)ε} and {kN:ψ(F^xkξ,p)ε}=I, implies that IFI(μ,v)limψ(F^xkξ,p)=0. Also, it is clear that (e) implies (b).

Theorem 2.2

Let (X,ϕ,ψ,,) be an IFNLS. If (xk) is Fibonacci I-convergent with regards to the IFN (ϕ,ω), then IFI(μ,v)limx is unique.

Proof.

Assume that there exist two distinct elements ξ1,ξ2X such that IFI(ϕ,ψ)limxk=ξ1 and IFI(ϕ,ψ)limxk=ξ2. Given ε(0,1), choose γ>0 such that (1γ)(1γ)>1ε and γγ<ε. So, for any p>0, we determine the following: Kϕ,1(γ,p)={kN:ϕ(F^xkξ1,p2)1γ},Kψ,1(γ,p)={kN:ψ(F^xkξ1,p2)γ},Kϕ,2(γ,p)={kN:ϕ(F^xkξ2,p2)1γ},Kψ,2(γ,p)={kN:ψ(F^xkξ2,p2)γ}. and Kϕ,ψ(γ,p)=(Kϕ,1(γ,p)Kϕ,2(γ,p))(Kψ,1(γ,p)Kψ,2(γ,p)). Since IFI(ϕ,ψ)limxk=ξ1 and IFI(ϕ,ψ)limxk=ξ2, all the sets Kϕ,1(γ,p), Kψ,1(γ,p), Kϕ,2(γ,p), Kψ,2(γ,p) and Kϕ,ψ(γ,p) belongs to I. This implies that its complement Kϕ,ψc(γ,p) is a non-empty set in F(I). Let mKϕ,ψc(γ,p). Then we have mKϕ,1c(γ,p)Kϕ,2c(γ,p) or mKψ,1c(γ,p)Kψ,2c(γ,p).

Case (i): Suppose that mKϕ,1c(γ,p)Kϕ,2c(γ,p). Then we have ϕ(F^xmξ1,p2)>1r, ϕ(F^xmξ2,p2)>1r and therefore ϕ(ξ1ξ2,p)ϕ(F^xmξ1,p2)ϕ(F^xmξ2,p2)>(1γ)(1γ)>1ε. Since ε>0 is arbitrary, we get ϕ(ξ1ξ2,p)=1 for all p>0, which yields ξ1=ξ2.

Case (ii): Suppose that mKψ,1c(γ,p)Kψ,2c(γ,p). Then, we have ψ(F^xmξ1,p2)<γ, ψ(F^xmξ2,p2)<γ and therefore ψ(ξ1ξ2,p)<ψ(F^xmξ1,p2)ψ(F^xmξ2,p2)<γγ<ε. Since arbitrary ε>0, we get ψ(ξ1ξ2,p)=0 for all p>0. This occurs that ξ1=ξ2. So, we conclude that IFI(ϕ,ψ)limx is unique.

Theorem 2.3

Suppose (X,ϕ,ψ,,) be an IFNLS, and x=(xk), y=(yk) be two sequences in X.

(a)

If (ϕ,ψ)limxk=ξ, then IFI(ϕ,ψ)limF^xk=ξ.

(b)

If IFI(ϕ,ψ)limF^xk=ξ1 and IFI(ϕ,ψ)limF^yk=ξ2, then IFI(ϕ,ψ)lim(F^xk+F^yk)=(ξ1+ξ2);

(c)

If IFI(ϕ,ψ)limF^xk=ξ and α be any real number, then IFI(ϕ,ψ)limαF^xk=αξ.

Proof.

(a) As (ϕ,ψ)limxk=ξ, so for each ε>0 and p>0 there exists r0N such that ϕ(xkξ,p)>1ε and ψ(xkξ,p)<ε for all kr0. The set A={kN:ϕ(xkξ,p)1εorψ(xkξ,p)ε} is contained in {1,2,,r01}, then {kN:ϕ(F^xkξ,p)1εorψ(F^xkξ,p)ε}I, since I is admissible. This shows that IFI(ϕ,ψ)limxk=ξ.

(b) Let ε>0 be given. Choose γ>0 such that (1γ)(1γ)>1ε and γγ<ε. For any p>0, give Kϕ,1(γ,p)={kN:ϕ(F^xkξ1,p2)1γ},Kψ,1(γ,p)={kN:ψ(F^xkξ1,p2)γ},Kϕ,2(γ,p)={kN:ϕ(F^ykξ2,p2)1γ},Kψ,2(γ,p)={kN:ψ(F^ykξ2,p2)γ} and Kϕ,ψ(γ,p)=(Kϕ,1(γ,p)Kϕ,2(γ,p))(Kψ,1(γ,p)Kψ,2(γ,p)). Since IFI(ϕ,ψ)limxk=ξ1 and IFI(ϕ,ψ)limyk=ξ2, so for p>0, Kϕ,1(γ,p), Kψ,1(γ,p), Kϕ,2(γ,p), Kψ,2(γ,p) and Kϕ,ψ(γ,p) belongs to I. So, Kϕ,ψc(γ,p) is a non-empty set in F(I). We show that Kϕ,ψc(γ,p){kN:ϕ(F^(xk+yk)(ξ1+ξ2),p)>1εandψ(F^(xk+yk)(ξ1+ξ2),p)<ε}. Let mKϕ,ψc(γ,p). Then, we get ϕ(F^xmξ1,p2)>1γ,ϕ(F^ymξ2,p2)>1γψ(F^xmξ1,p2)<γ,ψ(F^ymξ2,p2)<γ. Now, we have ϕ(F^(xm+ym)(ξ1+ξ2),p)ϕ(F^xmξ,p2)ϕ(F^ymξ2,p2)>(1γ)(1γ)>1ε and ψ(F^(xm+ym)(ξ1+ξ2),p)ψ(F^xmξ,p2)ψ(F^ymξ2,p2)<γγ<ε. This shows that Kϕ,ψc(γ,p){kN:ϕ(F^(xk+yk)(ξ1+ξ2),p)>1εandψ(F^(xk+yk)(ξ1+ξ2),p)<ε}. Since Kϕ,ψc(γ,p)F(I). Hence IFI(ϕ,ψ)lim(xk+yk)=(ξ1+ξ2).

(c) Case (i): When α=0, for all ε>0 and p>0, ϕ(F^0xk0ξ,p)=ϕ(0,p)=1>1ε and ψ(F^0xk0ξ,p)=ω(0,p)=0<ε. It gives us (ϕ,ψ)lim0xk=θ, and by part (i), we get IFI(ϕ,ψ)limF^0xk=θ.

Case (ii): When α0. As IFI(ϕ,ψ)limxk=ξ, for each ε>0 and p>0, (1) A={kN:ϕ(F^xkξ,p)>1εandψ(F^xkξ,p)<ε}F(I).(1) To show the result it is enough to prove that for each ε>0 and p>0, A{kN:ϕ(αF^xkαξ,p)>1εandψ(αF^xkαξ,p)<ε}. Let mA. Then, we get ϕ(F^xmξ,p)>1ε and ψ(F^xmξ,p)<ε. Now, ϕ(αF^xmαξ,p)=ϕ((F^xmξ),p|α|)ϕ(F^xmξ,p)ϕ(0,p|α|p)=ϕ(F^xmξ,p)1=ϕ(F^xmξ,p)>1ε and ψ(αF^xmαξ,t)=ψ((F^xmξ),p|α|)ψ(F^xmξ,p)ψ(0,p|α|p)=ψ(F^xmξ,p)0=ψ(F^xmξ,p)<ε Hence, we have A{kN:ϕ(αF^xkαξ,p)>1εandψ(αF^xkαξ,p)<ε}. But (Equation1) shows that IFI(ϕ,ψ)limαF^xk=αξ.

Before the next theorem, we recall the following:

Let (X,ϕ,ψ,,) be an IFNLS. The open ball BxI(p,ε)(F^) with center at x and radius p w.r.t. parameter of fuzziness 0<ε<1 is given as BxI(p,ε)(F^)={y=(yk)X:ϕ(F^(x)F^(y),p)1εorψ(F^(x)F^(y),p)ε}I where p>0. A subset A of X is called IF-bounded if there exists p>0 and 0<ε<1 such that ϕ(F^y,p)>1ε and ψ(F^y,p)<ε for all yA.

Let l(ϕ,ψ)(X) denotes the space of all IF-bounded sequences whereas by I(ϕ,ψ)(X) we denote the space of all IF-bounded and I-convergent sequences in (X,ϕ,ω,,). Now, we have the following theorem.

Theorem 2.4

Let (X,ϕ,ψ,,) be an IFNLS. Then IFI(ϕ,ψ)(X) is a closed linear space of l(ϕ,ψ)(X).

Proof.

It is clear that I(ϕ,ψ)(X) is a subspace of l(ϕ,ψ)(X). Next, we prove the closedness of I(ϕ,ψ)(X). As I(ϕ,ψ)(X)I(ϕ,ψ)(X)¯ provides, so we show that I(ϕ,ψ)(X)¯I(ϕ,ψ)(X). Let xI(ϕ,ψ)(X)¯. Then, BxI(p,ε)I(ϕ,ψ)(X), for each open ball BxI(p,ε) centered at x and radius p w.r.t. parameter of fuzziness 0<ε<1. Taking yBxI(p,ε)I(ϕ,ψ)(X), p>0 and ε(0,1). Choosing γ(0,1) such that (1γ)(1γ)>1ε and γγ<ε. As yBxI(p,ε)I(ϕ,ψ)(X), there exists a subset KN such that KF(I) and for all kK, we get ϕ(F^xkF^yk,p2)>1γ, ψ(F^xkF^yk,p2)<γ, ϕ(F^yk,p2)>1γ, ψ(F^yk,p2)<γ. But for all kK, we get ϕ(F^xk,p)=ϕ(F^xkF^yk+F^yk,p)ϕ(F^xkF^yk,p2)ϕ(F^yk,p2)>(1γ)(1γ)>1ε and ψ(F^xk,p)=ψ(F^xkF^yk+F^yk,p)ψ(F^xkF^yk,p2)ψ(F^yk,p2)<γγ<ε. It gives K{kN:ϕ(F^xk,p)>1εandψ(F^xk,p)<ε}. Since KF(I), it concludes that {kN:ϕ(F^xk,p)>1εandψ(F^xk,p)<ε}F(I). Therefore, we get xI(ϕ,ψ)(X).

Theorem 2.5

All open ball with center at x and radius p w.r.t. parameter of fuzziness 0<ε<1, i.e. BxI(p,ε)(F^) is an open set in c(ϕ,ψ)I(F^).

Proof.

Examine the open ball BxI(p,ε)(F^) with center at x and radius p w.r.t. parameter of fuzziness 0<ε<1, BxI(p,ε)(F^)={y=(yk)X:ϕ(F^(x)F^(y),p)1εorψ(F^(x)F^(y),p)ε}I. Then (BxI)c(p,ε)(F^)={y=(yk)X:ϕ(F^(x)F^(y),p)>1εandψ(F^(x)F^(y),p)<ε}F(I). Assume y=(yk)(BxI)c(p,ε)(F^). Then, the set {y=(yk)X:ϕ(F^(x)F^(y),p)>1εandψ(F^(x)F^(y),p)<ε}F(I). For ϕ(F^(x)F^(y),p)>1εandψ(F^(x)F^(y),p)<ε there is a p0(0,p) so that ϕ(F^(x)F^(y),p0)>1εandψ(F^(x)F^(y),p0)<ε. Taking ε0=ϕ(F^(x)F^(y),p0) means ε0>1ε. Then, there exists u(0,1) so that ε0>1u>1ε. For ε0>1u, we get ε1,ε2(0,1) such that ε0ε1>1u and (1ε0)(1ε0)<u. Take ε3=max{ε1,ε2}. Consider the open ball ByI(pp0,1ε3)(F^). We have to denote ByI(pp0,1ε3)(F^)BxI(p,ε)(F^).

Assume z=(zk)(ByI)c(pp0,1ε3)(F^), then {kN:ϕ(F^(xk)F^(zk),pp0)>ε3andψ(F^(xk)F^(zk),pp0)<1ε3}F(I). So ϕ(F^(x)F^(z),p)ϕ(F^(x)F^(y),p0)ϕ(F^(y)F^(z),pp0)ε0ε3ε0ε1>1u>1ε, hence {kN:ϕ(F^(xk)F^(zk),p)>1ε}F(I), and ψ(F^(x)F^(z),p)ψ(F^(x)F^(y),p0)ψ(F^(y)F^(z),pp0)(1ε0)(1ε3)(1ε0)(1ε2)<u<ε, hence {kN:ψ(F^(x)F^(z),p)<ε}F(I). Therefore the set {kN:ϕ(F^(xk)F^(zk),p)>1εandψ(F^(xk)F^(zk),p)<ε}F(I). So z=(zk)(ByI)c(p,ε)(F^). As a result, we get (ByI)c(pp0,1ε3)(F^)(ByI)c(p,ε)(F^). We prove BxI(p,ε)(F^) is an open set in c(ϕ,ψ)I(F^).

Theorem 2.6

The spaces c(ϕ,ψ)I(F^) and c0(ϕ,ψ)I(F^) are Hausdorff spaces.

Proof.

It is clear that c0(ϕ,ψ)I(F^)c(ϕ,ψ)I(F^). We have to prove the result for only c(ϕ,ψ)I(F^). Assume x=(xk), y=(yk)c(ϕ,ψ)I(F^) such that xy. At that time, for all pN, we get 0<ϕ(F^xkF^yk,p)<1,0<ψ(F^xkF^yk,p)<1. Presume ε1=ϕ(F^xkF^yk,p),ε2=ψ(F^xkF^yk,p), and ε=max{ε1,1ε2}. Afterwards, for all ε0>ε there are ε3,ε4(0,1) so that ε3ε3ε0, (1ε4)(1ε4)(1ε0). Again suppose ε5=max{ε3,ε4} and contemplate the open balls BxI(1ε5,p2)(F^) and ByI(1ε5,p2)(F^) centered at x and y respectively. Then, we demonstrate that BxI(1ε5,p2)(F^)ByI(1ε5,p2)(F^)=. If possible assume z=(zk)BxI(1ε5,p2)(F^)ByI(1ε5,p2)(F^). Then, we obtain ε1=ϕ(F^xkF^yk,p)ϕ(F^xkF^zk,p2)ϕ(F^zkF^yk,p2)>ε5ε5ε3ε3ε0>ε1,ε2=ψ(F^xkF^yk,p)ψ(F^xkF^zk,p)ψ(F^zkF^yk,p2)<(1ε5)(1ε5)(1ε4)(1ε4)<(1ε0)<ε2. From the above equations we obtain a contradiction. So, BxI(1ε5,p2)(F^)ByI(1ε5,p2)(F^)=. As a result, the space c(ϕ,ψ)I(F^) is a Hausdorff space.

Definition 2.2

Let (X,ϕ,ψ,,) be an IFNLS and IP(N) be a nontrivial ideal. A sequence x=(xk) in X is named Fibonacci I-Cauchy with regards to the IFN (ϕ,ψ) or IFI(ϕ,ψ)-Cauchy sequence if, for all ε>0 and p>0, there exists a positive integer N so that Kε(F^):={kN:ϕ(F^xkF^xN,p)1εorψ(F^xkF^xN,p)ε}I.

Theorem 2.7

Let (X,ϕ,ψ,,) be an IFNLS. Then a sequence x=(xk) in X Fibonacci I-convergent with regards to the IFN (ϕ,ψ) iff it is Fibonacci I-Cauchy with regards to the IFN (ϕ,ψ).

Proof.

Necessity. Let x=(xk) in X Fibonacci I-convergent to ξ with regards to the IFN (ϕ,ψ), i.e. IFI(ϕ,ψ)limxk=ξ. For a given ε>0, choose γ>0 such that (1γ)(1γ)>1ε and γγ<ε. Since IFI(ϕ,ψ)limxk=ξ, we get (2) K(F^)={kN:ϕ(F^xkξ,p)1γorψ(F^xkξ,p)γ}I(2) for all p>0, which implies that Kc(F^)={kN:ϕ(F^xkξ,p)>1γorψ(F^xkξ,p)<γ}F(I). Let mKc(F^). But for p>0, we have ϕ(F^xmξ,p)>1γ or ψ(F^xmξ,p)<γ. Taking B(F^)={kN:ϕ(F^xkF^xm,p)1εorψ(F^xkF^xm,p)ε};p>0, to show the result it is sufficient to prove B(F^) is contained in K(F^). Let kB(F^), then we have ϕ(F^xkF^xm,p2)1γ or ψ(F^xkF^xm,p2)γ, for p>0. We have two possible cases.

Case (i): We consider ϕ(F^xkF^xm,p)1ε. So, we have ϕ(F^xkξ,p2)1γ and then, kK(F^). As otherwise i.e. if ϕ(F^xkξ,p2)>1γ, then we have 1εϕ(F^xkF^xm,p)ϕ(F^xkξ,p2)ϕ(F^xmξ,p2)>(1γ)(1γ)>1ε; which is impossible. Hence, B(F^)K(F^).

Case (ii): If ψ(F^xkF^xm,p)ε, we have ψ(F^xkξ,p2)>γ and therefore kK(F^). As otherwise i.e. if ψ(F^xkξ,t2)<γ, we get εψ(F^xkF^xm,p)ψ(F^xkξ,p2)ψ(F^xmξ,p2)<γγ<ε; which is impossible. Hence, B(F^)K(F^). Thus, in all cases, we get B(F^)K(F^). By (Equation2) B(F^)I. This shows that (xk) in X Fibonacci I-Cauchy sequence.

Sufficiency. Let x=(xk) in X Fibonacci I-Cauchy with respect to the IFN (ϕ,ψ) but not Fibonacci I-convergent with regards to the IFN (ϕ,ψ). Then there exists r such that A(ε,p)(F^):={kN:ϕ(F^xkF^xr,p)1εorψ(F^xkF^xr,p)ε}I and B(ε,p)(F^)={kN:ϕ(F^xkξ,p2)>1εorψ(F^xkξ,p2)<ε}I equivalently, B(ε,p)c(F^)F(I). Since ϕ(F^xkF^xr,p)2ϕ(F^xkξ,p2)>1ε, and ψ(F^xkF^xr,p)2ψ(F^xkξ,p2)<ε, If ϕ(F^xkξ,p2)>(1ε)2 and ψ(F^xkξ,p2)<ε2, respectively, we have A(ε,p)c(F^)I, and so A(ε,p)(F^)F(I), which is a contradiction, as x=(xk) was Fibonacci I-Cauchy with respect to the IFN (ϕ,ψ). Hence, x=(xk) must be Fibonacci I-convergent with regards to the IFN (ϕ,ψ).

Definition 2.3

Assume that (X,ϕ,ψ,,) is an IFNLS. A sequence x=(xk) in X is called Fibonacci I-convergent to ξX with regards to IFN (ϕ,ψ) if there exists a subset M={k1,k2,:k1<k2<} of N such that MF(I) and ϕ,ψlimnxkn=ξ. The element ξ is called the Fibonacci I-limit of the sequence (xk) with regards to IFN (ϕ,ψ) and it is demonstrated by IFI(ϕ,ψ)limxk=ξ.

Theorem 2.8

Let (X,ϕ,ψ,,) be an IFNLS and IP(N) be a nontrivial ideal. If IFI(ϕ,ψ)limxk=ξ then IFI(ϕ,ψ)limxk=ξ.

Proof.

Suppose that IFI(ϕ,ψ)limxk=ξ. Then M={k1,k2,:k1<k2<}F(I) such that (ϕ,ψ)limnxkn=ξ. For all ε>0 and p>0 there exists an integer N>0 such that ϕ(xknξ,p)>1ε and ψ(xknξ,p)<ε for all n>N. Since {nN:ϕ(xknξ,p)>1εorψ(xknξ,p)<ε}I. Hence, {kN:ϕ(F^xkξ,p)>1εorψ(F^xkξ,p)<ε}H{k1<k2<<<kN1}I. for all ε>0 and p>0. As a result, we conclude that IFI(ϕ,ψ)limxk=ξ.

3. Conclusion

In the current study, using the concept of Fibonacci sequence, we have introduced the new notion of Fibonacci ideal convergent sequence in IFNLS. We have shown that these sequences follow many properties similar to that of classical real-valued sequences. Further, Fibonacci I-Cauchy sequences have been introduced and the Fibonacci I-completeness of an IFNLS has been established. Finally, the concept of Fibonacci I-convergence, which is stronger than Fibonacci ideal convergence, has been investigated. Several intuitionistic fuzzy Fibonacci ideal convergent spaces have been established and significant features of these spaces have been obtained.

Disclosure statement

No potential conflict of interest was reported by the author(s).

Additional information

Notes on contributors

Ömer Kişi

Ömer Kişi received the BSc degree from Cumhuriyet University, Sivas, Turkey in 2007; MS from Cumhuriyet University, Sivas, Turkey in 2010 and PhD degree in mathematical analysis worked with Fatih Nuray from Afyon Kocatepe University, Afyonkarahisar, Turkey in 2014. Started his career as an research assistant at Cumhuriyet University in 2009; then assistant professor at Bartın University, Bartın, Turkey in 2014. Since 2019, he has been a associate professor at the Department of Mathematics, Bartın, Turkey; his area of expertise includes summability theory, sequences spaces, and fuzzy sequence spaces through functional analysis.

Pradip Debnath

Pradip Debnath is an assistant professor (in mathematics) in the Department of Applied Science and Humanities of Assam University, Silchar (a central university), India. His research interests include Fuzzy Logic, Fuzzy Graphs, Fuzzy Decision Making, Soft Computing and Fixed-Point Theory. He has published over 50 papers in various journals of international repute. He is a reviewer for more than 20 international journals including Elsevier, Springer, IOS Press, Taylor and Francis and Wiley. He has successfully guided Ph.D. students in the areas of Fuzzy Logic, Soft Computing and Fixed-Point Theory. At present, he is working on a major Basic Science Research Project funded by UGC, Government of India. He received a gold medal in his postgraduation from Assam University, Silchar and qualified several national level examinations in mathematics.

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